Just last week, General Motors announced the return of the Hummer nameplate as a new all-electric pickup under the GMC brand. The announcement of the GMC Hummer EV truck was replete with wild and impressive specs, not the least of which was GM’s claim that the new vehicle will produce an Earth-twisting 11,500 pound-feet of torque. However, the question is this: just how realistic is that torque rating?
While electric vehicles are indeed known for producing some rather impressive torque (at zero rpm, no less), 11,500 pound-feet is a number that seems completely out of step with reality – or at the very least, anything a civilian can buy and drive on public roads. So what gives?
The answer is likely that General Motors is calculating the new GMC Hummer EV torque rating using a somewhat non-standard method, possibly multiplying the torque through a specific drive ratio, rather than measuring the torque output directly out of the electric drive motors.
As such, it’s difficult to calculate what the GMC Hummer EV is really laying down, but given our recent exclusive that the pickup will be making about 1,000 horsepower and reach 60 mph in three seconds, we’re thinking low four-figure torque numbers would make sense – something like 1,100 to 1,400 pound-feet.
While not quite as mind-blowing as 11,500 pound-feet, figures like those are still quite impressive, even up against diesel-powered trucks like the Chevrolet Silverado 3500HD, which makes 910 pound-feet of torque from its 6.6L L5P V8 tubo-diesel Duramax.
Nevertheless, we can’t wait to learn more about the upcoming GMC Hummer EV pickup. Built on the new GM BT1 vehicle platform, the new truck will be produced at the Detroit-Hamtramck Assembly plant in Michigan. A debut is slated for May, so stay tuned.